C Program to Find the Number of Integers Divisible by 5

This C Program calculates the number of integers divisible by 5. This program checks if the given number is divisible by 5 and then prints an appropriate message.

Here is source code of the C program to calculate the number of integers divisible by 5. The C program is successfully compiled and run on a Linux system. The program output is also shown below.

1. /*

2.  * C program to find the number of integers divisible by 

3.  * 5 between the given range num1 and num2, where num1 < num2.

4.  *

5.  * Also find the sum of all these integer numbers which are divisible

6.  * by 5 and display the total.

7.  */

8. #include <stdio.h>

10. void main()

11. {

12.     int i, num1, num2, count = 0, sum = 0;

14.     printf("Enter the value of num1 and num2 \n");

15.     scanf("%d %d", &num1, &num2);

16.     /* Count the number and compute their sum*/

17.     printf("Integers divisible by 5 are \n");

18.     for (i = num1; i < num2; i++)

19.     {

20.         if (i % 5 == 0)

21.         {

22.             printf("%3d,", i);

23.             count++;

24.             sum = sum + i;

25.         }

26.     }

27.     printf("\n Number of integers divisible by 5 between %d and %d =

28.  %d\n", num1, num2, count);

29.     printf("Sum of all integers that are divisible by 5 = %d\n", sum);

30. }

$ cc pgm18.c
$ a.out
Enter the value of num1 and num2
12 17
Integers divisible by 5 are
 15,
Number of integers divisible by 5 between 12 and 17 = 1
Sum of all integers that are divisible by 5 = 15